Please, titration 1 and 2, as well as Average molarity of the Naoh solution and
ID: 542604 • Letter: P
Question
Please, titration 1 and 2, as well as Average molarity of the Naoh solution and Average deviation. THANK YOU!
Explanation / Answer
Ans 1 :
The molar mass of the compound will be :
=(6 x 1.008) + (2 x 12.01) + (6 x 16)
= 126.07 g
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