A 500 mL of 3.2M NaNO3 solution is diluted to 1.2L. What is the molarity of the

Question

A 500 mL of 3.2M NaNO3 solution is diluted to 1.2L. What is the molarity of the diluted solution? To what volume should you dilute 375mL of a 10.0M H2S0, solution to obtain a 0.150M H2SO solution? Consider the following reaction: Li2S(aq) + Co(NOg)2(aq) 2LiNOg(aq) + CoS(s) What volume of 0.150M Li2S solution is required to completely react with 150mL of 0.250M Co(NO3)2? Classify each compound as a strong electrolyte (SE) or a nonelectrolyte (NE). Circle the answe a) MgBr SE/NE, b) Ci2H220 SEINE c) CH3OH SE/NE; d) HCI SE/ NE Determine whether each compound is soluble (S) or insoluble (). Circle the answer.

Explanation / Answer

Q1

We need to apply dilution law, which is based on the mass conservation principle

initial mass = final mass

this apply for moles as weel ( if there is no reaction, which is the case )

mol of A initially = mol of A finally

or, for this case

moles of A in stock = moles of A in diluted solution

Recall that

mol of A = Molarity of A * Volume of A

then

moles of A in stock = moles of A in diluted solution

Molarity of A in stock * Volume of A in stock = Molarity of A in diluted solution* Volume of A in diluted solution

Now, substitute known data

500*3.2 = 1200*M2

M2 = 500*3.2/1200 = 1.333 M

Q2

M1*V1 = M"*V2

375*10 = 0.150 * V2

V2 = 375*10 /0.150 = 25000 mL = 25 L

Q3

mol of Co(NO3)2 = MV = 150*0.25 = 37.5 mol of Co(NO3)2

ratio is 1:1 so

37.5 mol of Li2S required

V = mol/M = 37.5/0.15 = 250 mL required

Q4

SE = will dissoaciate 100%

MgBr2; HCl only

NE = C12H22O11 (moleuclar and CH3OH ( molecular)

Q5

KNO3 = soluble,

Agi = not solubl

(NH4)2S = soluble

CocO3 = not soluble

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