1) A solution of acetic acid PKA= 4.75 has a pH of 6.75, the radio of acid to co
ID: 542203 • Letter: 1
Question
1) A solution of acetic acid PKA= 4.75 has a pH of 6.75, the radio of acid to conjure in CH3COOH-CH3COO^++H^-.2) the PH of blood is 7.4 while gastric juice is 1.4. How much mole time more H+ or less in gastric juice? 1) A solution of acetic acid PKA= 4.75 has a pH of 6.75, the radio of acid to conjure in CH3COOH-CH3COO^++H^-.
2) the PH of blood is 7.4 while gastric juice is 1.4. How much mole time more H+ or less in gastric juice?
2) the PH of blood is 7.4 while gastric juice is 1.4. How much mole time more H+ or less in gastric juice?
Explanation / Answer
1)
pH = 6.75
pKa = 4.75
pH = pKa + log [salt / acid]
6.75 = 4.75 + log [CH3COO- / CH3COOH]
log [CH3COO- / CH3COOH] = 2
ratio [CH3COO- / CH3COOH] = 100
2)
pH of blood = 7.4
[H+] = 3.98 x 10^-8 M
pH of gastric juice = 1.4
[H+] = 0.0398 M
ratio = [gastric juice] / blood
= 0.0398 / 3.98 x 10^-8
[gastric juice] = 1 x 10^6 [blood]
1x 10^6 times more.
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