Savannah State University Department of Chemistry and Forensic Science CHEM 4531

Question

Savannah State University Department of Chemistry and Forensic Science CHEM 4531 Advanced Organic Chemistry Fall 2017 -Chemistry Test 1, 2 Chance This is an opportunity to improve your grad You should not allow anyone to copy your work. You may have group stud must not be exactly the same. You will be e. The due date is Tuesday October 17 at 10:00 am. y, but your solutions penalized 5 points for every 10 minutes of lateness. The e of the two tests (in class and this take home) will the grade for Test 1. Name: Date: October 17, 2017 @ 10:00 am Part I (50 points) 1. In molecular orbital (MO) theory, the molecular orbital of highest energy that is occupied with an electron is referred to as: A) degenerate. B) LCAO- CLUMO D) HOMO, E) antibonding. 2. When the 1s orbitals of two hydrogen atoms combine to form a hydrogen molecule, which molecular orbitals are formed? A) One bonding molecular orbital only C) Two antibonding molecular orbitals E) One bonding molecular orbital and one antibonding molecular orbital B) Two bonding molecular orbitals D) Three bonding molecular orbitals 3. For a bond forming reaction involving donation of electrons between atoms, electron density is transferred into which molecular orbital of the accepting atom? A) s orbital B) p orbital C) d orbital D)H 4. The nitrogen atom's lone pair of electrons are contained in what orbital type? B) sp C) sp D) s E) p 5. Which carbons in the following molecule are sp' hybridized? A) Carbons I and II B) Carbons III and IVC) Carbons II and III D) Carbons I and III E) Carbons II and IV 6. How many s-sp bonds are in the following molecule? H-C-C-c-C-c A) 2 C) 4 D) 5 E) 6

Explanation / Answer

1. (D) HOMO

2. (E)

3. (E) LUMO

4 (A) sp2. As we can see the N has a double bond, it means one of it's p orbital is not involved in hybridization and forms pi bond, so N is sp2 hybridized.

5. (C) I and III. Since these two carbons forms a double bond, i. e. one of the p orbital is involved in pi bond formation.

6. (D) 5. Since here 4 carbons are having single double bond, i. e. they are sp2 hybridized, and they form 5 bonds with H, and thus with s orbital.

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