(2) The equilabrium constant K for the reaction fre is 3.8 × 10-s at 727°C Calcu
ID: 541772 • Letter: #
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(2) The equilabrium constant K for the reaction fre is 3.8 × 10-s at 727°C Calculate Ke and K, for the equilibrium at the same temperature (3) For the reaction at 700 C, A-0.534. Calculate the number of moles of H; that are present at equilibrium if a mixture of 0.400 mole of CO and 0.400 mole of H:O is heated to 700 C in a 10.0-L container. (4) The equilibrium constant Ke for the reaction is 4.2 at 1650°C. Initially 0.80 mol H: and 0.80 mol CO, are injected into a 5.0-L. flask. Calculate the concentration of each species at equilibrium. (5) Consider the reaction 250,(g)+048) 250,(g) !"--1982 kumol in the concentrations of SO2. O, and SO, at equilibrium if we were to (a) increase the e pressure; (c) increase SO2: (d) add a catalyst; (e) add helium at constant volume. temperature; (b) increase the (6) Consider the equilibrium system for the following situations: (a) initially only 3A , Sketch the changes in the concentrations of A and B over time A is present; (b) initially only B is present; (e) initially both A and e present (with A in higher concentration). In each case, assume that the concentration of B is higher than that of A at equilibrium.Explanation / Answer
According to lechatlier's principle,
a. increase in the temperature,the equilibirum moves to back because backward reaction is endothermic.
i.e., SO3 cocnentration decreases and SO2 & O2 concentration increases.
b. inreasing the pressure, the equilibrium moves to right
i.e., SO2 & O2 concentration decreases, SO3 concentration increases.
c. increase SO2, the equilibrium moves to right
i.e., SO2 & O2 concentration decreases, SO3 concentration increases
d. by adding of catalyst, there is no change in equilibrium.
e. by adding of He gas no change in equilibrium
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