0.00, 0.183 8.04, 0.0915 24.1, 0.0458 56.2, 0.0229 a)Use the graph to determine
ID: 541736 • Letter: 0
Question
0.00, 0.183
8.04, 0.0915
24.1, 0.0458
56.2, 0.0229
a)Use the graph to determine the half life reaction in which a 0.183 M solution of A was allowed to react?________
b)Is the 1/2 of this reaction dependent/indepedent of conc?____________
c)Calculate the half life of the subsequent experiment in which a 1.56 M solution of A was allowed to react____________
Time(sec) Concentration (M) 0.183 0.0915 0.0458 0.0229 0 8.04 24.1 56.2 Concentration (M) vs Time (sec) 0.2 0.18 0.16 0.12 0.1 0.08 0.06 0.04 0.02 0 y =-0.0024x + 0.1389 0 10 20 30 40 50 60 Time SecondsExplanation / Answer
a)Use the graph to determine the half life reaction in which a 0.183 M solution of A was allowed to react?________
Half life --> time reuqired to achieve 50% of reactants
form the list
[A]0 = 0.183 --> [A]50% = 0.183/2 = 0.0915 M
from the graph
t = 8.04 seconds
b)Is the 1/2 of this reaction dependent/indepedent of conc?____________
get the 2nd half life:
[A]0 = 0.0915 --> [A]50 = 0.0915 /2 = 0.04575
t = (24.1 -8.04) = 16.06
the half life is TWICE that of the original value, therefore, it DOES depends on the initial concentration
c)Calculate the half life of the subsequent experiment in which a 1.56 M solution of A was allowed to react____________
We need k
for 2nd order
half life = 1/(k*[A])
16.06 = 1/(k*0.04575)
k = 1/(16.06*0.04575) = 1.3610
now..
assume k is the same so
Rate = k*C^2
half life = 1/(k*[A]0new)
half life = 1/(1.3610*(1.56))
half life = 0.4709 s
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