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0.00, 0.183 8.04, 0.0915 24.1, 0.0458 56.2, 0.0229 a)Use the graph to determine

ID: 541736 • Letter: 0

Question

0.00, 0.183

8.04, 0.0915

24.1, 0.0458

56.2, 0.0229

a)Use the graph to determine the half life reaction in which a 0.183 M solution of A was allowed to react?________

b)Is the 1/2 of this reaction dependent/indepedent of conc?____________

c)Calculate the half life of the subsequent experiment in which a 1.56 M solution of A was allowed to react____________

Time(sec) Concentration (M) 0.183 0.0915 0.0458 0.0229 0 8.04 24.1 56.2 Concentration (M) vs Time (sec) 0.2 0.18 0.16 0.12 0.1 0.08 0.06 0.04 0.02 0 y =-0.0024x + 0.1389 0 10 20 30 40 50 60 Time Seconds

Explanation / Answer

a)Use the graph to determine the half life reaction in which a 0.183 M solution of A was allowed to react?________

Half life --> time reuqired to achieve 50% of reactants

form the list

[A]0 = 0.183 --> [A]50% = 0.183/2 = 0.0915 M

from the graph

t = 8.04 seconds

b)Is the 1/2 of this reaction dependent/indepedent of conc?____________

get the 2nd half life:

[A]0 = 0.0915 --> [A]50 = 0.0915 /2 = 0.04575

t = (24.1 -8.04) = 16.06

the half life is TWICE that of the original value, therefore, it DOES depends on the initial concentration

c)Calculate the half life of the subsequent experiment in which a 1.56 M solution of A was allowed to react____________

We need k

for 2nd order

half life = 1/(k*[A])

16.06 = 1/(k*0.04575)

k = 1/(16.06*0.04575) = 1.3610

now..

assume k is the same so

Rate = k*C^2

half life = 1/(k*[A]0new)

half life = 1/(1.3610*(1.56))

half life = 0.4709 s