ELAB QUESTIONS student performs this lab and obtains the followi ng data. Comple

Question

ELAB QUESTIONS student performs this lab and obtains the followi ng data. Complete the table and answer the questions below. Compound selected for analysis Mass of crucible and cover (g) Mass of crucible, cover, and hydrated sample (8) Mass of hydrated sample (g) Mass of crucible, cover, and dehydrated sample- I weighing ( Mass of crucible, cover, and dehydrated sample 2 weighing (g4.0363 g Mass of crucible, cover, and dehydrated sample-3weighing (g Massofcrucible,cover,anddehydratedsample-4mweighing(e) 4.0332g Mass of dehydrated sample (g) Mass of water evolved (g) CuSO 3.2000 g 4.5000 g 4.0407 g 4.0332 8 1110 Labs

Explanation / Answer

Mass of hydrated sample= 4.5-3.2= 1.3g

Average mass of crucible, cover and dehydrated sample=(4.0407+4.0363+4.0332+4.0332)/4= 4.03585g

Mass of dehydrated sample= 4.03585-3.2= 0.83585g

Mass of water evolved= mass of hydrated - mass of dehydrated sample= 1.3-0.83585= 0.46415g

# moles of water= 0.46415/18= 0.0257 moles

# moles of dehydrated CuSO4= 0.83585/159.609= 0.00523 moles

Ratio of water to CuSO4= 0.0257/0.00523= 4.9= 5

Formula= CuSO4.5H2O

Copper sulfate pentahydrate

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