4. Given that 4H--393.5 kJ for the rxn. given that AH=-2858 kJ for the rxn: give
ID: 541643 • Letter: 4
Question
Explanation / Answer
Ans 4 :
Lets number the reactions from 1 to 3 top to bottom.
Now multiply the reaction 1 by 2 and the reaction 2 by 3 , and then both the reactions together.
Subtract the reaction 3 from this reaction to get the desired reaction.
So the Delta H for the desired reaction = 2(-393.5) + 3(-285.8) + (+84.7)
= -1559.7 KJ
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