Use the following information to calculate the lattice energy of potassium chlor

Question

Use the following information to calculate the lattice energy of potassium chloride.

I. Ionization energy of K (g): 425 kJ/mol
ii. Electron affinity of Cl (g): -349 kJ/mol
iii. Energy of sublime K (s): 89 kJ/mol
iv. Bond energy of Cl2 (g): 240 kJ/mol
v. (Delta)Hf (KCl (s) ) : -438 kJ/mol

Use the following information to calculate the lattice energy of potassium chloride. i. ii. iii. iv. v. Ionization energy of K (g) : 425 kJ/mol Electron affinity of Cl (g):-349 kJ/mol Energy to sublime K (s): 89 kJ/mol Bond energy of Cl2 (g): 240 k]/mol , (KCl (s) ) :-438 kJ/mol

Explanation / Answer

Given that;

I. Ionization energy of K (g): 425 kJ/mol
ii. Electron affinity of Cl (g): -349 kJ/mol
iii. Energy of sublime K (s): 89 kJ/mol
iv. Bond energy of Cl2 (g): 240 kJ/mol
v. (Delta)Hf (KCl (s) ) : -438 kJ/mol

H_f(KCl (s)) = H_s(K(s)) + (1/2)·BE(Cl-Cl) + I(k) - EA(Cl) - UL

=>
UL = H_s(K(s)) + (1/2)·BE(Cl-Cl) + I(K) - EA(Cl) - H_f(KCl(s))
= 89.kJ/mol + (1/2)·240 kJ/mol + 425 kJ/mol – 349 kJ/mol
- (- 438 kJ/mol)

= 723 kJ/mol

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