My answer i got was -13.8 is that correct what i did was 66+136.3=202.3-101.1-11

Question

My answer i got was -13.8 is that correct what i did was 66+136.3=202.3-101.1-115=-13.8kcal/mol

Use the bond dissociation energies of the following table to estimate the molar change in free energy of the reaction of H2C-CH2 and H-F to yield H3C-CH2F: Some Homolytic Bond Dissociation Energies Number 1-1 36.1 kcal/mol H-CH2CH3 101.1 13.8 kcal/ mol kcal/mol Br-Br46.1 kcal/mol H3C-CH3 90.1 kcal/mol | 59.0 kcal/mol 38.0 kcal/mol H-H 104.2 kcal/molI-CH3 Cl-Cl | H2C=CH2 | 66.0 (T bond) | H2C=CH2 | kcal/mo | 174.1 F-F (total) 57.6 72.1 83.7 kcal/mol kcal/mol kcal/mol H-l 71.3 kcal/molBr-CH3 H-Br87.5 kcal/mol C-CH3 kcal/mol 115.0 kcal/mol H-CI103.2 kcal/mol F-CH3

Explanation / Answer

Solution for the problem:

Equation: CH2=CH2 + HF ------------. CH3CH2F

Left hand side:

C-H bond dissociatio energy = 66.0 k.cal/ mole

H-F bond dissociatio energy = 136.3 k.cal/ mole

-------------------

202.3 k.cal/ mole

Right hand side:

C-F bond dissociatio energy = 115.0 k.cal/ mole

C-H bond dissociatio energy = 101.1 k.cal/ mole

____________________

216.1 k.cal/ mole

Difference of energy = RHS-LHS = -ve value

216.1 k.cal/ mole - 202.3  k.c al/ mole

= - 13.8 k.c al/ mole

   The calculated answer is correct

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