The Edison storage cell is symbolized: Fe(s)|FeO(s)|KOH(aq, a)||Ni_2O_3(s)|NiO(s

Question

The Edison storage cell is symbolized: Fe(s)|FeO(s)|KOH(aq, a)||Ni_2O_3(s)|NiO(s)|Ni(s). The half-cell reactions are: Ni_2O_3(s) + H_2O(l) + 2e^- rightarrow 2NiO(s) + 2OH^- FeO(s) + H_2O(l) + 2e^- rightarrow Fe(s) + 2OH^- standard electrode potentials: E^0 = 0.45V E^0 = -0.87V What is the initial electrochemical cell potential (EMF)? If a miniaturized version containing 1.5mg of the active materials were assembled, what would its initial electrode potential be? (ignore the iron and nickel electrodes).

Explanation / Answer

Ans. Eo = Ecathode - Eanode

Eo = E(Ni2O3/NiO) - E(FeO/Fe)

Eo = 0.45 - (-0.87) = 1.32V

Ecell = Eo - 0.059/2 *log(OH-)1^2 / (OH-)2^2

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.