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What is the correct symbol for an alpha particle? a. ^4_2 alpha b. ^4_1 alpha c.

ID: 539287 • Letter: W

Question

What is the correct symbol for an alpha particle? a. ^4_2 alpha b. ^4_1 alpha c. ^2_4 alpha d. ^2_2 alpha e. ^0_0 alpha A homogeneous mixture of two or more substances is called _____ a. a compound. b. a solvent c. a solution. d. a mess e. an electrolyte Which combination of quantum numbers would be allowed for one subshell containing five orbital a. n = 5, l = 0 b. n = 2, l = 4 c. n = 3, l = 2 d. n = 4, l = 4 e. n = 1, l = 0 What ion would you predict element 118 would form? a. +1 b. -1 c. 0 (unlikely to form an ion) d. +2 e. -2

Explanation / Answer

22. a. The correct symbol for an alpha particle is A. Alpha particle has 2 protons and 2 neutrons making its atomic number 2 and atomic mass = 2+2 = 4

23. c. By definition, a solution is a homogeneous mixture of 2 or more substances. It could be in any phase- solid, liquid or gas.

24. c. The correct combination is n=3 and l=2. According to the rules of quantum numbers,

The quantum numbers in standard use are:

n= principal quantum number

l= angular quantum number

m= azimuthal quantum number

if n=3, l can be 0,1,2. Here, l=2. Thus, this is valid.

For l=2, m = -2,-1,0,1,2 (or m range from -l to l, thus taking 2l+1 values). Each value of m- the azimuthal quantum number represents possible orientations of the orbitals. Thus, for l=2, m can take 5 values, hence 5 possible orbitals. Thus, the option chosen.

25. c. The element has a noble gas like configuration.

We know this because:

The atomic number of Radon( the earlier noble gas ) is 86.

Now, by the Aufbau principle, the orbitals with lower energys fill up first. Thus, the electron filling takes place in the following manner:

[Rn] 5f14, 6d10, 7s2, 7p6

These amount to a total of 32 electrons. Thus, the total electrons is: 86+32 = 118. In this configuration, the valence orbital is completely filled. This also coincides with the atomic number given here. Thus, the atomic configuration will be noble gas like and the element most likely form no ion ( 0 oxidation state)

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