Balance the following chemical reaction in acidic conditions using the lowest po

Question

Balance the following chemical reaction in acidic conditions using the lowest possible whole number coefficients. (Enter coefficients for one and zero. Blanks will be market incorrect.) Unbalanced Reaction: Mn_2 O_3 (s) + Cl^- (aq) rightarrow Mn^2+ (aq) + HClO_2 (aq) Balanced Reaction: Mn_2 O_3 (s) + 1 Cl^- (aq) + 0 H_2 O (l) + 0 OH^- (aq) + 9 H^+ (aq) rightarrow 4 Mn^2+ (aq) + 1 HClO_2 (aq) + 4 H_2 O (l) + 0 OH^- (aq) + 0 H^+ (aq) Balance the following chemical reaction in basic conditions using the lowest possible whole number coefficients. (Enter coefficients and zero- blanks will be marked incorrect.) Unbalanced Reaction + AgO(s) rightarrow H_2 BO_3^- (aq) + Ag_2 O(s) Balanced Reaction: B(s) + 4 AgO(s) + 0 H_2 O(l) + 6 OH^- (aq) + 0 H^+ (aq) rightarrow 1 H_2 BO_3^- (aq) + 2 Ag_2 O(s) + 2 H_2 O(l) + 0 OH^- (aq) + H^+ (aq)

Explanation / Answer

Q2

balance in basic conditions:

Split in half cells

B(s) = BO3-3(aq)

AgO(s) = Ag2O(s)

Balance Ag:

B(s) = BO3-3(aq)

2AgO(s) = Ag2O(s)

balance O addin H2O

3H2O + B(s) = BO3-3(aq)

2AgO(s) = Ag2O(s) + H2O

balance H+

3H2O + B(s) = BO3-3(aq) + 6H+

2H+ + 2AgO(s) = Ag2O(s) + H2O

balance charge

3H2O + B(s) = BO3-3(aq) + 6H+ + 3e-

2e- + 2H+ + 2AgO(s) = Ag2O(s) + H2O

balance e-

6H2O + 2B(s) = 2BO3-3(aq) + 12H+ + 6e-

6e- + 6H+ + 6AgO(s) = 3Ag2O(s) + 3H2O

add all

6H2O + 2B(s) + 6e- + 6H+ + 6AgO(s) = 3Ag2O(s) + 3H2O +  2BO3-3(aq) + 12H+ + 6e-

cancel common terms

3H2O(l) + 2B(s) + 6AgO(s) = 3Ag2O(s) +  2BO3-3(aq) + 6H+(aq)

add OH- so it is basic conditino

6OH-(aq) + 3H2O(l) + 2B(s) + 6AgO(s) = 3Ag2O(s) +  2BO3-3(aq) + 6H+(aq) + 6OH-(aq)

6OH-(aq) + 3H2O(l) + 2B(s) + 6AgO(s) = 3Ag2O(s) +  2BO3-3(aq) + 6H2O(l)

cancel H2O

6OH-(aq) 2B(s) + 6AgO(s) = 3Ag2O(s) +  2BO3-3(aq) + 3H2O(l)

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