The following pictures represent mixtures of cis-C_2H_2X_2 molecules and trans-C
ID: 539037 • Letter: T
Question
The following pictures represent mixtures of cis-C_2H_2X_2 molecules and trans-C_2H_2X_2 molecules, which interconvert according to the equation cis-C_2H_2X_2 trans-C_2H_2X_2. If mixture (1) is at equilibrium, which of the other mixtures are also at equilibrium? A) mixture (2) B) mixture (3) C) mixture (4) D) None of the other mixtures are at equilibrium. The following pictures represent mixtures of A_2B_4 molecules and AB_2 molecules, which interconvert according to the equation A_2B_4 2 AB_2. If mixture (1) is at equilibrium, which of the other mixtures are also at equilibrium? A) mixture (2) B) mixture (3) C) mixture (4) D) None of the other mixtures are at equilibrium.Explanation / Answer
36) we have a mixture of cis and trans isomers. The mixture (1) represents the mixture is at equilibrium,
So, at equilibrium, we have 2 cis molecules and 6 trans molecules. Therefore, at equilibrium, we have 1: 3 ratio of cis: trans isomers.
Mixtu2: contains 3 cis and 3 trans isomers. The ratio of cis-trans isomers is 1:1, so it not at equilibrium
Mixture 3: contains 1 cis and 3 trans isomers. The ratio of cis-trans isomers is 1:3, this at equilibrium
mixture 4: contains 3 cis and 1 trans isomer. The ratio of cis-trans isomers is 3:1. Therefore, it is not at equilibrium
Hence, the option (B), the mixture (3) is correct.
37) A2B4 <--> 2AB2
Given that mixture (1) is at equilibrium. We have 2 A2B4 and 2 AB2 molecules. The ratio of A2B4/AB2 is 1:1
Mixture (2) = contains 1 molecule A2B4 and 1 molecule AB2, the ratio A2B4/AB2 is 1:1. Hence, it is at equilibrium.
Mixture (3) = contains 1 molecules of A2B4 and 2 molecule of AB2, the ratio A2B4/AB2 is 1:2. Hence it is not at equilibrium
mixture (4) = contains 8 molecules of A2B4 and 4 molecules of AB2, the ratio A2B4/AB2 is 2:1. Hence, it is not at equilibrium
Hence, the option (A), mixture (2) is correct.
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