Answer the following questions related to the given electrochemical cell. 1. Wha
ID: 536868 • Letter: A
Question
Answer the following questions related to the given electrochemical cell.
1. What is E°cell (in V)? Report your answer to two three decimal places in standard notation (i.e., 0.123 V). 0.741 V
2. The electrochemical cell is comprised of a Tl electrode in a 6.06 × 10-4 M solution of Tl3+ (aq) coupled to a Pt electrode in a solution containing H+ (aq) where the pH of the solution is 1.60 and the partial pressure of H2(g) is 0.809 atm. The temperature of the cell is held constant at 25°C.
(a)What is Ecell (in V) for the electrochemical cell? Report your answer to three decimal places in standard notation (i.e., 0.123 V)
(b) If the pH of the the cell compartment on the right is increased to 3.17 while other the partial pressures and concentrations remain the same as in question 2, what will be the new Ecell (in V)? Report your answer to three decimal places in standard notation (i.e., 0.123 V).
Tl3+(aq) + 3e Tl(s)E° = 0.741 V 2H+(aq) + 2e H2(g)
E° = 0.000 V
Explanation / Answer
1. Cell reaction,
2Tl3+ + 3H2 --> 2Tl + 6H+
Eocell = Ecathode - Eanode
= 0.741 - 0 = 0.741 V
2. pH = -log[H+] = 3.17
[H+] = 6.76 x 10^-4 M
Ecell = Eocell - 0.0592/n logQ
= 0.741 - 0.0592/6 log[(6.76 x 10^-4)^6/(6.06 x 10^-4)^2.(0.809)^3]
= 0.799 V
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