Advance Study Assignment: Rate of Reactions, ll. A clock Reaction 1. A student s

Question

Advance Study Assignment: Rate of Reactions, ll. A clock Reaction 1. A student studied the clock reaction deseribed in this experiment. She set up Reaction Mixture 3 by mixiag 10 ml. o 010 M 10 ml. 0.0010 M Nazsao,. 20 mL oo40 M KBro and 10 mL 0.10 M HCI using the procedure given. It took about 40 seconds for the color to turi blue. a. She found the concentrations of each reactant in the reacting mixture by realizing that the number of moles of each reactant did not change when that reactant was mixed with the others, but that its concentration did. For any reactant A. The volume of the mixture was 50 mL Revising the equation, she obtained V (mL) Find the concentrations of each reactant by using the above equation. 20 M. (H b. What was the relative rate of the reaction (000t)? 40 c. Knowing the relative rate of reaction for Mixture 3 and the concentrations of I-, Bros and H in that mixture, she was able to set up Equation 5 for the relative rate of the reaction. The only quantities that remained unknown were k', m, m, and p. Set up presuming she did. t property 2. For Reaction Mixture 1 the student found that 75 seconds were required. On dividing Equation 5 for Reaction Mixture Equation 5 for Reaction Mixture 3, and after canceling out the common terms (k', terms in a and (H she got the following equation 13.3 (0.0040) (1) 0.0080 gnizing that 13.3/25 is about equal to 112, she obtained an approximate value for n. What was that value? (continued on following page)

Explanation / Answer

given

13.3/25= (1/2)n, n is the order of reaction

1/2= (1/2)n, taking ln, ln (1/2)= n*ln(1/2)

hence n=1

the rate equation becomes (-r)= K[BrO3-]

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