Adenosine monophosphate (AMP) is a regulatory molecule in metabolic processes su

Question

Adenosine monophosphate (AMP) is a regulatory molecule in metabolic processes such as glycolysis and gluconeogenesis. For example, it stimulates the glycolytic enzyme phosphofructokinase, and therefore ATP production, and it inhibits the gluconeogenic enzyme fructose 1,6-bisphosphatase. Adenylate kinase catalyzes the reversible reaction shown here:

2ADP --> ATP + AMP

During periods of intense activity, when glycolysis is used in the generation of ATP, the reaction lies to the right, decreasing [ADP], generating ATP, and accumulating AMP. However, [ATP] is usually much greater than [ADP], and [ADP] is greater than [AMP]. Determine [AMP] when 3% of the ATP in a hypothetical cell is hydrolyzed to ADP. In this cell, the initial concentration of ATP is 273 M, and the total adenine nucleotide concentration (the concentration of ATP, ADP, and AMP) is 382 M. The equilibrium constant K is 0.82

What is the concentration of AMP after 3% of the ATP is hydrolyzed to ADP?

Please explain what is happening in the solution posted, I want to be able to understand what I am doing wrong.

Explanation / Answer

ATP=273,

ATP,ADP,AMP=382,

ADP+AMP=382-273=109,

k=            (ADP)2 / (ATP)(AMP)

0.82=(ADP)2 / 273*(109-(ADP) or

(adp)2 +273*0.82*(adp)-273*109*0.82 = 0

quadratic equation whose solution

ADP=24.5

AMP=84.5

ATP=273

if ATP concentarion falls 3% then atp=264.81mM

AMP+ADP= 382-264.81=117.19mM

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