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1. The vapor pressure of ethanol (C2H5OH) at 20°C is 44 mmHg, and the vapor pres

ID: 534668 • Letter: 1

Question

1. The vapor pressure of ethanol (C2H5OH) at 20°C is 44 mmHg, and the vapor pressure of methanol (CH3OH) at the same temperature is 94 mmHg. A mixture of 28.1 g of methanol and 45.9 g of ethanol is prepared and can be assumed to behave as an ideal solution.

Calculate the vapor pressure of methanol and ethanol above this solution at 20°C. Be sure to report your answers to the correct number of significant figures.

Ethanol: ____mmHg

Calculate the mol fraction of methanol and ethanol in the vapor above this solution at 20°C.

Methanol _____

Ethanol _____

2.

[CH2(OH)CH2(OH)] would you add to a car radiator containing 7.50 L of water if the coldest winter temperature in your area is 20.5°C? Calculate the boiling point of this water-ethylene glycol mixture. (The density of ethylene glycol is 1.11 g/mL.)

°C

3. Calculate the percent by mass of the solute in each of the following solutions:


(a) 5.03 g of NaBr in 71.1 g of solution

% NaBr

(b) 32.5 g of KCl in 183 g of water

% KCl

(c) 3.81 g toluene in 33.1 g benzene

% toluene

Be sure to answer all parts.

How many liters of the antifreeze ethylene glycol

[CH2(OH)CH2(OH)] would you add to a car radiator containing 7.50 L of water if the coldest winter temperature in your area is 20.5°C? Calculate the boiling point of this water-ethylene glycol mixture. (The density of ethylene glycol is 1.11 g/mL.)


What is the volume of antifreeze?

L

What is the boiling point of the solution?

°C

Explanation / Answer

Ans 1. The molar mass of Methanol =32.04 g / mol

Number of moles of Methanol =28.1 / 32.04 = 0.878 moles

Molar mass of Ethanol = 46.07 g / mol

Number of moles of Ethanol= 45.9 / 46.07 = 0.996 moles

Mole fraction of Methanol = 0.878 / ( 0.878 + 0.996) = 0.469

Partial vapour pressure of Methanol = 94 x 0.469 = 44.07 mmHg

Mole fraction of Ethanol=0.531

Partial vapour pressure of Ethanol = 44 x 0.531= 23.36 mmHg

Total vapour pressure of the solution = 44.07 + 23.36 = 67.4 mm Hg