1. The activation energy for the denaturation of a protein is 311.0 kJ/mol. At w
ID: 534654 • Letter: 1
Question
1. The activation energy for the denaturation of a protein is 311.0 kJ/mol. At what temperature will the rate of denaturation be 19 percent greater than its rate at 25.00°C?
_____°C
2. The thermal decomposition of N2O5 obeys first-order kinetics. At 45°C, a plot of ln[N2O5] versus t gives a slope of 7.30 × 104 min1. What is the half-life of the reaction?
___ × 10___min (Enter your answer in scientific notation.)
3. What rate constant can be determined from only the half-life of a reaction?
a) Zeroth
b) First
c) Second
d) Third
e) The rate constant cannot be determined using only a rate constant for any reaction.
4.
X ---> Y
X --> Z
5. Consider the following unbalanced equation:
A + B C
When C is being formed at the rate of 0.086 M/s, A is being consumed at a rate of 0.172 M/s and B is being consumed at a rate of 0.172 M/s. Balance the equation based on the relative rates of formation and consumption of products and reactants.
6. The reaction
2A + 3B C is first order with respect to A and B. When the initial concentrations are [A] = 1.80 × 102M and [B] = 2.11 ×103M, the rate is 4.89 ×104M/s.
Calculate the rate constant of the reaction.
Enter your answer in scientific notation.
___×10___
M
M1
s
s1
M/s
·
7. The rate constant for the following second-order reaction is 0.80/(M ·s) at 10°C.2NOBr(g) 2NO(g) + Br2(g)
Calculate the half-life when [NOBr]0 = 0.070 M.
_____ s
9.
rate = k[A]t
X ---> Y
X --> Z
The ratio of k1/k2 at 40°C is 5.5. What is the ratio at 311°C? Assume that the frequency factors of the twoo reactions are the same.
Ratio = In [Alo kt
Explanation / Answer
1) Ans we know the Arrhenius equation,
ln( k2/k1 ) = (Ea/R) x (1/T1 - 1/T2)
rate of denaturation k1 =100
rate of denaturation k2=100+19=119
Ea = 311.00 kJ/mol =311x1000 =311000 J/mol
R = 8.3144 ( is rate constant)
T1 = 25 °C =273+25 =298 K
T2 = ?
ln(119/100) = (311000/8.3144)x(1/298 - 1/T2)
ln(1.19) = (37404.98)(1/298 - 1/T2)
0.1740=(37404.98/298 )-(37404.98/T2)
(37404.98/T2)=125.5201 -0.1740
T2=37404.98/125.3461
T2=298.4 K
T2=298.4 - 273= 25.4°C
T2= 25.4°C
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