35 List the compounds in decreasing boiling point order. CH3 CH2CH3 CH3CN A) CH3

Question

35 List the compounds in decreasing boiling point order. CH3 CH2CH3 CH3CN A) CH3 CH2CH3 B) Ar CH3CH2CH3 CH3CN CH3CN Ar C) CH3CH CH3 Ar CH3CN D) CH3CN CH3CH2CH3 Ar 36) In liquid propanol, CH3CH2CH20H, which intermolecular forces are present? A) Dispersion, hydrogen bonding and dipole-dipole forces are present. BO Only dipole-dipole and ion-dipole forces are present. C) Only dispersion and dipole-dipole forces are present. D) Only hydrogen bonding forces are present 37) The normal boiling point for H2Se is higher than the normal boiling point for H2S.This can be explained by A) larger dipole-dipole forces for H2Se B) larger dispersion forces for H2Se larger hydrogen-bond forces for H2Se D) larger dipole-dipole forces, larger dispersion forces, and larger hydrogen-bond forces for H2Se 38) What is the strongest type of intermolecular force present in CHBr3? A) ion-dipole B) dispersion C) hydrogen bonding D) dipole-dipole 39) Choose the molecule or compound that exhibits dipole-dipole forces as its strongest intermolecular force. A) H2 B) SO2 C) NH3 D) CF4 E) BC13 40) Place the following compounds in order of increasing strength of intermolecular forces. NH2CH3 CS2 B) 12 NH2CH3 CS2. A) NH2CH3 CS2 12 D) 12 CS2 NH2CH3 41) Which of the following compounds has the highest boiling point? A) H20 B) H Cl C) H2S D) N H3

Explanation / Answer

35)

CH3CN is polar in nature and hence the interaction between CH3CN will be dipolar interaction

So, CH3CN will have maximum boiling point since other 2 compounds are non polar

Molar mass of CH3CH2CH3 is more than Ar, so vanderwaal’s force will be stronger in CH3CH2CH3

So, boiling point will be least in case of Ar

Answer: D

36)

H is attached to oxygen. So, it will form hydrogen bonding

Since CH3CH2CH2OH is polar, it will have dipole-dipole force as well.

Dispersion force is present in all compound

Answer: A

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