Number 9. What is the composition (as % alpha anomer) of the equilibrium depicte

Question

Number 9.

What is the composition (as % alpha anomer) of the equilibrium depicted in Figure 1 given that the specific rotation of the equilibrium is +300°?

Please carry maximum number of significant figures through to final answer then round to a whole integer number. Do not include units.

Question 9 1.4 pts What is the composition (as alpha anomer) ofthe equilibrium depicted in Figure 1 given that the specific rotation of the equilibrium is +300o? Please carry maximum number of significant figures through to final answer then round to a whole integer number. Do not include units. Figure 1 Sugar X, alpha anomer Sugar X, open-chain form Sugar X, beta anomer [a]D 240 1%

Explanation / Answer

see, we have specific rotation, +300

alpha anomer= 240

beta anomer= 320

a(+240degree) + b(320) = +300 degree

There is the open chain form present, so the fraction present as the anomer (a) plus the fraction present as the anomer (b) should account for all the glucose a+b = 1 or b = 1-a.

Thus a(+240degree) + (1-a)(320) =300 degree

240 a + 320-320a =300

80a =300-320

a= 0.25 or 25 %

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