Please help by answering all of the questions! Greatly appercaited!! Kp - 3.6 Co

Question

Please help by answering all of the questions! Greatly appercaited!!

Kp - 3.6

Compound Amount (mg) - 1400

Volume of Ch2Cl2 (ml) - 550

Volume of Water (mL) - 700

Part 1 – Single Extraction
You will be performing a single using the data above. Your compound has a Kp as listed. Calculate the following:

a) How much compound will remain in the water layer after a single extraction using the volume of water indicated above and DOUBLE the volume of CH2Cl2 indicated above?

b) How much compound was extracted into the CH2Cl2 layer?

c)What percentage of the original sample (the “Compound Amount (mg)” column) ended up in the CH2Cl2 layer?

Part 2 – Double Extraction
You will be performing a double extraction using the data above. Your compound has a Kp as listed. Calculate the following:

d)How much compound will remain in the water layer after a first extraction using the volume of water and the volume of CH2Cl2 indicated above?

e) How much compound went into the CH2Cl2 after the first extraction

f) If the water layer from the end of part (d) is extracted one more time with the same amount of CH2Cl2, how much compound will remain in the water layer?

g) How much compound was extracted into the CH2Cl2 layer the second time?
h )What is the combined amount of compound that was extracted into the CH2Cl2 layers during both extractions?

i) What percentage of the original sample (the “Compound Amount (mg)” column) ended up in the combined CH2Cl2 layers from parts (d) and (f)?

j) Notice that you used the same amount of CH2Cl2 during the Single Extraction as you did during the Double Extraction. Which method extracted a greater amount of the compound out of the water layer?

k )Note that it takes a lot more time to do a double extraction than a single extraction. Is the time worth it, if each extraction takes 30 minutes? Use the conditions below.

Question: If you are paid $65/hour how valuable must your compound be (in $/g) to justify doing two extractions (as in Part 2) instead of just one extraction (as in Part 1).

The key to answering this question is to :

i. calculate the extra money you have to spend to do 2 extractions instead of just 1 (this is your extra cost).

(Extra time of labor) x (wage)

ii. calculate the extra amount of your compound that you gained by doing 2 extractions versus doing only a

single extraction (this is your benefit). Answer h– answer b

iii. divide i/ii to get $/mg

Explanation / Answer

Extraction,

Single extraction

let x amount of sample is extracted in organic solvent CH2Cl2

Compound mass = 1.4 g

Kp = amount in CH2Cl2/amount in water

3.6 = (x/550)/[(1.4 - x)/700]

0.0072 - 0.00514x = 0.00182x

x = 0.0072/0.00696 = 1.03 g

amount extracted in CH2Cl2 by single extraction = 1.03 g

amount remaining in water = 1.4 - 1.03 = 0.37 g

Double extraction

let x amount of sample is extracted in organic solvent CH2Cl2 after first extraction

Compound mass = 1.4 g

Kp = amount in CH2Cl2/amount in water

3.6 = (x/275)/[(1.4 - x)/700]

0.0072 - 0.00514x = 0.00364x

x = 0.0072/0.00878 = 0.82 g

amount extracted in CH2Cl2 after first extraction = 0.82 g

amount remaining in water after first extraction = 1.4 - 0.82 = 0.58 g

Second extraction

3.6 = (x/275)/[(0.58 - x)/700]

0.003 - 0.00514x = 0.00364x

x = 0.003/0.00878 = 0.34 g

amount extracted in CH2Cl2 after two extraction = 0.82 + 0.34 = 1.16 g

amount remaining in water after two extraction = 1.4 - 1.16 = 0.24 g

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