Short Answer Titration Lab Experiment 1: Perform a Coarse Titration Lab Results
ID: 532524 • Letter: S
Question
Short Answer
Titration Lab
Experiment 1: Perform a Coarse Titration
Lab Results
For your coarse titration record the following results.
volume of NaOH solution in the burette at the start (mL)
volume of NaOH solution in the burette at the end (mL)
volume of NaOH solution dispensed (mL)
volume of HCl solution in the flask (mL)
Data Analysis
Calculate the molarity of the HCl concentration using your coarse titration results.
Experiment 2: Perform a Fine Titration
Lab Results
For your fine titration record the following results.
volume of NaOH solution in the burette at the start (mL)
volume of NaOH solution in the burette at the end (mL)
volume of NaOH solution dispensed (mL)
volume of HCl solution in the flask (mL)
Data Analysis
Calculate the molarity of the HCl concentration using your fine titration results.
Conclusions
What do you expect to happen if you forget to add phenolphthalein to the Erlenmeyer flask?
Suppose you had to titrate a solution of NaOH of unknown concentration with a solution of HCl of known concentration using phenolphthalein as an indicator. How will you determine the color change?
Suppose you titrated a sample of acetic acid (monoprotic acid) with a 0.125 M solution of NaOH. Given the data in the table below, what is the concentration of the acetic acid solution?
volume of NaOH solution in the burette at the start (mL)
volume of NaOH solution in the burette at the end (mL)
volume of NaOH solution dispensed (mL)
volume of HCl solution in the flask (mL)
Explanation / Answer
If the indicator phenolphthalein is not added, we wold not be able to identify the end point of the acid-base titration.
When NaOH is titrated with HCl using phenolphthalein indicator, the color changes from pink (basic) to colorless (acidic) at the end point.
Titration : Acetic acid + NaOH
moles NaOH used = 0.125 M x 22.40 ml = 2.8 mmol
concentration of acetic acid = 2.8 mmol/15 ml = 0.187 M
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.