can I have help with this one as well. Analytical Chemistry Guided Inquiry Activ

Question

can I have help with this one as well.

Analytical Chemistry Guided Inquiry Activity .Predicting Acid/Base Titration Curves Titration 2.0.1069 Naco are dissolved in a 100 valumetric flask which is filled to the mark with DI The full 100 mL are transferred to a 250 mL Erlenmeyer, and then titrated with M a)Titrand species: b) Titrant species: c) Molecular equation to describe reaction oftitrand and titrant species d) Total nic equation to describe reaction of titrand and titrant species e) Net ionic equation to describe reaction of titrand and titrant species TI) Titrant mill f Titrand milli-moles equivalents at equivalence m) Titrant milli g)Titrand milli- moles at equivalents equivalence h) Titrant volume added at (final) equivalence pt. mL i) Total volume at (final equivalence (ml) j) Nalat equivalence

Explanation / Answer

a) Titrand species - Titrand is the substance which is being analysed in the titration. Hence here titrand species is Na2CO3

b) Titrant species - Titrant is the compound in the titration buret of known concentration. Hence here titrant species is 0.0532 M HCl.

c) Molecular equation -

Na2CO3 (s) + 2HCl (aq) = 2NaCl (aq) + CO2 (g) + H2O (l)

d) Total ionic equation -

2Na+ + CO32- + 2H+ + 2Cl- = 2Na+ + 2Cl- +  CO2 (g) + H2O (l)

e) Net ionic equation - (cancelling common ions from both sides of total ionic equation)

CO32- + 2H+ = CO2 (g) + H2O (l)

f). Millimoles of Na2CO3 = (mass/ molar mass) x 1000

= (0.1069 / 106) x 1000

= 1 millimole

g) No of milliequivalents of Na2CO3 = (1069 x 2) / 106 = 20.17 [(wt. in mg x valency) / molar mass]

h) Titrant volume added at equivalence point =( 2 x 100 ) / (0.0532 x 1000)

= 3.76 mL

i) Total volume at equivalence point = 100 + 3.76 = 103.76 mL

j) Concentration of Na+ at equivalence point = 2x1 millimole = 2 millimole

l) Titrant miliequivalence = (mmol/L) X valence = (0.0532x1000/1000) x 1 = 0.0532

k) Titrant millimoles at equivalence = 3.76 x 0.0532 = 0.2

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.