The percent composition (weight/volume %) of a solution of 4.0 g of KI in 250 mL
ID: 531743 • Letter: T
Question
The percent composition (weight/volume %) of a solution of 4.0 g of KI in 250 mL of solution (A) 1.6% KI (B) 16% KI (C) 62.5% KI (D) 0.016% KI The amount of NH_4Cl needed to prepare 1250 mL of a 4.0% (weight/volume) solution is: (A) 45.g NH_4Cl (B) 50.g NH_4Cl (C) 5.0 g NH_4Cl (D) 2.5 g NH_4Cl A certain antibiotic is supplied in liquid form as 50.0 mg in 5.00 mL How many mL are required for a dosage of 500, mg of the antibiotic? (A) 10.0 mL (B) 50.0 mL (C) 100.mL (D) 150 mL The molarity (M) of a solution of 35.0 grams of potassium hydroxide in 500 mL of solution is: (A) 0.125 M KOH (B)1.25 M KOH (C) 1.35 M KOH (D) 0.135 M KOHExplanation / Answer
Solved first four problems, post multiple question to get the remaining answers
Q22) The correct answer is Option C (II and IV)
Reason: In the first reaction, H is not balanced i.e. in the left hand side there exists one mole of H2 and in the right hand side there exists two moles of H2
In the third reaction, oxygen is not balanced
Q23)
Charles law states that when the pressure of the gas is constant, then Volume divided by Temperature will be a constant
V1/T1 = V2/T2=k
Correct answer is Option A
Q24)
PV = constant
P1V1 = P2V2
(1)(20.9) = P2(4)
P2 = 20.9/4 = 5.23 atm
Correct answer is Option A
25)
Density = Mass/Volume
Mass of ethylene glycol = Density * Volume = 1.11 g/mL * 417 mL = 463 g
Correct answer is Option B
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