lie DE Lab 6: Estimating the Calorie Content of Nuts 3. Will you be the gross en
ID: 531587 • Letter: L
Question
lie DE Lab 6: Estimating the Calorie Content of Nuts 3. Will you be the gross energy or the physiologic energy value of a peanut when you do the calculations for this experiment? Briefly explain. (2) With which food label value will you compare your experimental result when calculating the percent difference in your determination of energy content? Briefly explain. 4. A student followed the procedure of this experiment to determine the Caloric content of a Planter's cocktail peanut. The peanut studied had a mass of 0.609 g before combustion and 0.053 g after combustion. The energy released during combustion caused a 14.2°C increase in the temperature of 200.0 mL of water in the calorimeter. (1) Calculate the mass of peanut burned 2) calculate the mass in kg, of water present in the calorimeter, u Equation 6 (3) Calculate the amount of energy released, in Cal, from the burning peanut. (4) Calculate the amount of energy released per gram of peanut burned.Explanation / Answer
Q.4
(1)
Mass of peanut before combustion = 0.609g
Mass of peanut after combustion = 0.053g
Mass of peanut burned = Mass of peanut before combustion - Mass of peanut after combustion
Mass of peanut burned = 0.609 - 0.053
Mass of peanut burned = 0.556g
(2)
Energy released during combustion of peanut caused 200ml of water to raise 14.20C in calorimeter.
The water present in calorimeter = 200ml
density of water = 1 gm/ml
mass of water in calorimeter = density of water * volume of water
mass of water in calorimeter = 1 * 200
mass of water in calorimeter = 200 gm
mass of water in calorimeter = 0.2 kg
(3)
The amount of energy release by combustion of peanut is absorbed by water in calorimeter to raise its temperature.
Specific heat of water (Cp) = 1 Cal/g0C
mass of water (m) = 200gm
Rise in temperature of water (dT) = 14.20C
The amount of heat absorbed by water in calorimeter = m*Cp*dT
The amount of heat absorbed by water in calorimeter = 200*1*14.2
The amount of heat absorbed by water in calorimeter = 2840 Cal
The amount of heat released by burning peanut = 2840 Cal
(4)
Mass of peanut before combustion = 0.609g
Energy released by combustion of peanut = 2840 Cal
Amount of energy released per gram of peanut = Energy released / Mass of peanut
Amount of energy released per gram of peanut = 2840 / 0.609
Amount of energy released per gram of peanut = 4663.383 Cal/gm
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