The reaction between selenious acid and the iodide ion in an acidic solution is

Question

The reaction between selenious acid and the iodide ion in an acidic solution is H_2Se_2O_3 + 6 l^- + 4 H^+ rightarrow 2Se + 2 I_3^- + 3 H_2 O The data given in the following table were measured at the same temperature. Determine the orders of the reaction with respect to each of the reactants. For the reaction above, what effect will tripling the concentration of the hydrogen ion while holding the other two reactants" concentrations constant have on the rate of the reaction? What is the overall order of the reaction?

Explanation / Answer

a) from the experimantal data

when [H2Se2O3] doublled rate also doublled

so with respect to [H2Se2O3] reaction is first order

when concentration of H+  doublled rate also doublled

so with respect to H+   reaction is first order

when concentration of I-  change rate does not change.

so with respect to I-   order = 0

rate = K [H2Se2O3][H+]

b) if H+   triplled rate also will be triplle.

because with respect to H+  ion reaction is first order.

c) overall order = 1 + 1 +0 = 2

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