of the following reactions is delta S degree at 25 degree C closest to zero? Exp
ID: 530285 • Letter: O
Question
of the following reactions is delta S degree at 25 degree C closest to zero? Explain your answer A) N_2 (g) + O_2 (g) rightarrow 2NO(g) B) H_2 (g) + I_2 (s) rightarrow 2HI (g) C) CH_3 CHO(g) + 5/2 O_2 (g) rightarrow 2CO_2 (g) + 2H_2 O (g) D) 2NO (g) + O_2 (g) rightarrow 2NO_2 (g) E) C_2 H_4 (g) + Br_2 (l) rightarrow C_2 H_4 Br_2 (l) For which of the following reactions is delta S degree > 0 at 25 degree C? Explain your answer A) 2H_2 (g) + O_2 (g) rightarrow 2H_2 O (g) B) 2ClBr(g) rightarrow Cl_2 (g) + Br_2 (g) C) I_2 (g) rightarrow I_2 (s) D) 2NO(g) + O_2 (g) rightarrow 2NO_2 (g) E) NH_4 HS(s) rightarrow NH_3 (g) + H_2 S(g) Assuming delta H and delta S are constant with respect to temperature, under what conditions will chemical reaction be spontaneous only at low temperatures? A) delta H is negative, and delta S is negative. B) delta H is positive, and delta S is positive. C) delta S = 0, and delta H is positive. D) delta H = 0, and delta S is negative. E) none of these Which responses includes all of the following processes that are accompanied by a decrease entropy? Explain your answer 1) I_2 (s) rightarrow I_2 (g) 2) 2I (g) rightarrow I_2 (g) 3) 2NH_3 (g) rightarrow N_2 (g) + 3H_2 (g) 4) Mg^2+ (aq) + 2OH^- (aq) rightarrow Mg(OH)_2 (s)Explanation / Answer
(b)
(E) because 1 mol of solid is getting converted into 2 mol of gas substances. As solid is rigid but gas is highly random in nature, hence the entropy will be increased.
Entropy: Measure of disorderness.
(c)
(A) If deltaH negative and deltaS negative, then the reaction is spontaneous only at low temperatures.
For a reaction to be spontaneous, deltaG = deltaH - T deltaS = - ve.
(d)
(2) 2 I (g) -----------> I2 (g) is associated with decrease in entropy becuase 2 moles of gaseous reactants are getting converted into 1 mol of gaseous products. Less is the number of gas moles less is the randomness and hence less is the entropy.
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