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can you pleases help plot pKa1 pKa2 midpoints equivelnece point 1 equivelnece po

ID: 529715 • Letter: C

Question

can you pleases help plot

pKa1

pKa2

midpoints

equivelnece point 1

equivelnece point 1

and show calculations for them? thank you

Titration curve for pH vs. volume of NaoH 12.00 10.00 6.00 2.00 0.00 10.00 25.00 30.00 35.00 40.00 45.00 15.00 20.00 0.00 5.00 Volume of 0.1906M NaoH (in mL) Appendix A1: Part 1: Titration of a diprotic cid Volume of Measured NaoH burette volume of NaoH pH reading (mL added (mu) 2.000,5 2.261 2.43 13.3 13.8 2.68 15.7 6.2 2.84 16,8 7,3 3.07 17,8 18.3 3,40 18,8 19.3 4.20 19.4 9,9 5.15 19.9 20,4 5.49 20.3 20.8 5.71 20,7 5.91 21.4 21.9 6.10 22.4 22,9 6.30 23.7 6.50 25.5 6,71 27,6 28.1 6.92 29.9 30.4 7.13 32 32.5 7.32 33,8 34.3 7.53 35.3 35.8 7,89 37,2 8.00 37.5 8,40 38,4 9.29 39.1 9,6 10.23 39.1 39.6 10.55 39.7 40.2 10.6840 1 406 10.82 41.3 41,8 1.03 41,9

Explanation / Answer

For calculations:

pKa1

pKa2

equivelnece point 2 = must be the volume used when pH changes drastically ( second time is more visible)

So from the graph, V = 38 mL is approx

then

the half point, must be the FIRST neutralization

equivelnece point 1 = 38/2 = 19 mL

for midpoints:

midpoint 1 --> Veq1 /2 = 19 /2 = 9.5 mL (first point)

midpoint 2 --> Ve2 /2 = 19+9.5 = 28.5 mL (second point)

nte that the pH at such points are pKaa and pKa2 respectively

pH at V = 9.5 mL,

nearest point is pH = 2 so pKa1 = 2

for 2nd point

pKa2 --> pH at V = 28.5 mL --> 6.75 approx

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