1 cal = 4.18 J 1. Consider the above diagram with a built in semipermeable membr

Question

1 cal = 4.18 J 1. Consider the above diagram with a built in semipermeable membrane as shown: a) Suppose 0.20 M NaCl is placed in arm A and 0.30 M NaCl is placed in arm B both to the same levels initially. What would happen to the liquid levels after equilibrium has been reached? b) Supposed you had used 0.20 M NaNO_3 and 0.10 M CaCl_2, again both to the same levels initially. What would happen to the levels at equilibrium? c) Supposed you had used 0.15 M sucrose and 0.20 M glucose again both to the same levels initially. What happen to the levels at equilibrium? When 50.0 mL of 1.00 M HCl was mixed with 50.0 mL of 1.00 M NaOH in a calorimeter, the temperature rose from 25.0 degree C to 31.05 degree C. Calculate the heat change for the reaction, assuming that the total volume of the solution is 100.0 mL of density 1.0 g/mL, and specific heat 1.00 cal/(g. degree C). a). write a balanced equation for the reaction b). how many moles of HCl (aq) and NaOH have reacted? c). is the reaction exothermic or endothermic? d). how many calories are evolved in the reaction? e). what is Delta H for the above reaction in kJ/mol.

Explanation / Answer

Q1

a)

The soluion of A will increase in concentration, solution B will decrease in concentration

IF same volume were used, it is likey final concentatin is between 0.20 and 0.30 M, i.e. 0.25 M

b)

NaNO3 = 2 ions, 0.2 M = 0.4 M

CaCl2 = 3 ions = 0.1 = 0.3 M

NaNO3 ions will flow to CaCl2 which is lower in concentration (total ion concentratio)

c)

sucrose and glucose are similar in that they are molecular, will not dissociate

the glucose will go frm B to A,

Evnetually, they mix all

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