Our hair maintains its shape because the fibers of keratin that make up the hair

Question

Our hair maintains its shape because the fibers of keratin that make up the hair are bound with S-S (disulfide) bonds. The disulfide bonds are prone to reduction, are converted into thiols. Oxidation of thiols converts them back to disulfides. How do you apply chemistry of disulfides and thiols to the practical task of shaping your hair (curling or straightening)? (A) Treat the hair with an oxidizing agent, shape them, and fix the new shape with a reducing agent. (B) Treat the hair with an oxidizing agent, shape them, and fix the new shape with a reducing agent. (C) Shape your hair, fix the new shape by the sequential treatment with an oxidizing agent, and then with a reducing agent. (D) None of these chemical techniques can work with actual hair because the peptide bonds in proteins are more important than the disulfide bonds. Which of these alkenes will produce a more stable intermediate via a 12-hydride shift when it is reacted with HBr? What is the product for this sequence of reactions? Which of these functional group is at the highest oxidation state? (A) alcohol (B) aldehyde (C) alkane (D) carboxylic acid Which is an intermediate for this polymerization reaction? Where would the stretching signal for the -OH of as alcohol group appear in the IR spectrum? (A) 1600 cm^-1 (B) 1715 cm^-1 (C) 1800 cm^-1(D) 3300 cm^-1

Explanation / Answer

Ans 64 . B) Treat the hair with reducing agent, shape them , and fix the new shape with the oxidising agent .

In the process of rebonding and hair straightening , the hairs are treated with a reducing agent , so that the disulfide bonds of the hair are reduced to thiols . The hair are ironed or curled according to the client's choice and then the shape is fixed with the application of a oxidising agent also called as fixer. This fixer fixes the shape of hair , by converting thiols back to disulfide bonds.

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