The iron nuclide _26^56Fe lies near the top of the binding energy curve (Figure

Question

The iron nuclide _26^56Fe lies near the top of the binding energy curve (Figure 1) and is one of the most stable nuclides. What is the binding energy per nucleon (in joules) for the nuclide _26^56Fe (atomic mass of 55.9349 amu; 1 joule = 6.24EE12 MeV)? Cobalt-60 (t_1/2 = 5.26 y) is used in cancer therapy since the gamma rays it emits can be focused in small areas where the cancer located. A 5.00-g sample of Co-60 is available for cancer treatment. (a) What is its activity in Bq? (b) What is its activity in Ci (a) beta decay; (b) alpha decay; (c) positron emission; (d) beta decay; (e) alpha decay; 4.303 counts/min degree gC; 7.11.1 days 8.37 times 10 y 9.7810 MeV/nucleon 10 2.10 times 10^14 Bq b. 5.7 times 10^2 Ci

Explanation / Answer

Answer to Q9)

For Fe-56 nucleus, there will be 26 proton and (56-26) 30 neutron

Total mass of proton = 26 X 1.00728 u = 26.18928 u

Total mass of neutron = 30 X 1.00867 u = 30.2601 u

Total mass of nucleons= 26.18928 + 30.2601 = 56.44938 u

Actual mass of nucleons (given) = 55.93490 u

Mass defect (m) = 56.44938 -55.93490 = 0.51448 u

Binding energy = m•c2

For 1u, binding energy = 931.5 MeV

For 0.51448 u, binding energy = 931.5 MeV • 0.51448 u / 1u

= 479.2381 MeV

Binding energy per nucleon (Eb/A) = 479.2381 MeV / 55.9349 u

=8.568 MeV u-1

1 J = 6.24 X 1012 MeV

Binding energy per nucleon = 8.568 J u-1 / 6.24 X 1012

= 1.37 X 10-12 J u-1

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