Which of these would be the rate law for an E_2 reaction? a) rate k [RX] b) rate
ID: 528282 • Letter: W
Question
Which of these would be the rate law for an E_2 reaction? a) rate k [RX] b) rate = k[RX][Nucleophile] c) rate = k [Rx]^2 d) rate = k[Nucleophile]^2 For Problems 13 and 14, consider this reaction: CH_3CH_2CH_2 Br + NaSH rightarrow CH_2VH_2CH_2SH + NaBr What effect does doubling the concentration CH_3CH_2CH_2Br have? a) doubles the rate b) halves the rate c) quadruples the rate d) has no effect on the rate What effect does doubling the concentration of NasH have? a) doubles the rate (b) halves the rate b) quadruples the rate d) has no effect on the rate In the term "S_N1", what does the S stand for, what does the N stand for, and what does the 1 stand for? Why does this reaction not give the indicated product? CH_3 HC = CHBr CH_3 HC=CHN_3 Looking at the mass spectrum, how could you tell whether you had CH_3Br or C_7H_10? What would you see in the spectrum for CH_3Br, and what would you see in the spectrum of C_7H_10?Explanation / Answer
12) The answer is b)
13 ) The answer is a)
14) The answer is a)
15) S =Substitution
N = Nucleophilic
1 = Ini molecular
16) Leaving of Br- is inhibited by the presence of double bond
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