The ideal gas law: PV=nRT Show work 1) what is the pressure exerted by 3.00 gram

Question

The ideal gas law: PV=nRT

Show work

1) what is the pressure exerted by 3.00 grams of oxygen gas in at 2.00L container at 25 degrees C?

2) 2 NaN3(s)-->2 Na(s) + 3 N2

Calculate the volume of N2(g) produced at 21 degrees C and 823 mm Hg when 60.0g Nan3(s) decomposes. (molar mass of NaN3=65.02 g/mol)

Mixed practice:

3) a 200. mL sample of a gas at 25 degrees C undergoes a change in volume to 100. mL at constant pressure. What is the new temperature of the gas in Celcius?

4) If 3.20 L of a gas at 25 degrees Celcius and 732 torr undergo a change to 50. C and 2.70L, what is the new pressure of the gas?

Explanation / Answer

Q1.

Apply ideal gas law

PV = nRT

P = nRT/V

substitute data, T must be in K

T = 25°C = 298K

n = mass/MW = 3/32 = 0.09375 mol

so

P = (0.09375)(0.082)(298)/(2) = 1.1454 atm

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