A hydrogen bonded dimer is formed between 2-pyridine according to the reaction 2

Question

A hydrogen bonded dimer is formed between 2-pyridine according to the reaction 2-pyridine + 2-pyridine doubleheaarrow dimer A plot of the inverse of the relaxation time of the reaction versus equilibrium concentration of 2-pyridine in chloroform at 298 K results in a slope of 0.60 times 10^9 M^-1 s^-1 and an intercept of 0.15 times 10^9 s^-1. Determine the equilibrium and the rate constants characterizing the reaction. A. K = 4, k_1 = 6.0 times 10^8 M^-1 s^-1, k_.1 = 1.5 times 10^8 s^-1 B. K = 1, k_1 =6.0 times 10^8 M^-1 s^-1, k_.1 = 6.0 times 10^8 s^-1 C. K = 0.25, k_1 = 1.5 times 10^8 M^-1 s^-1, k_.1 = 6.0 times 10^8 s^-1 D. K = 4, k_1 = 1.5 times 10^8 M^-l s^-1, k_.1 = 6.0 times 10^8 s^-1 E. K = 1, k_1 = 1.5 times 10^8 M^-1 s^-1, k_.1 = 1.5 times 10^8 s^-1

Explanation / Answer

the answer is A

As slope will give the give rate constant of forward reaction = 0.6 * 109 M-1s-1 = 6.0 * 108 M-1s-1

intercept will give the rate constant of resverse direction reaction = 0.15 * 109 s-1 = 1.5 * 108 s-1

K = k1/k-1 =6.0 * 108 /1.5 * 108 = 4

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