In the U.S, wines are officially labelled as sparkling if the dissolved CO2 cont

Question

In the U.S, wines are officially labelled as sparkling if the dissolved CO2 content is greater than 3.92 grams of CO2 per liter of wine. These wines have a density of 1.002 g/ml. (Show all work. Thanks!)

A. Determine the minimum concentration (in ppm) of CO2 a sparkling wine can contain.

B. Determine this minimum CO2 level as a molar concentration (M).

C. Determine the partial pressure of CO2 (in atmospheres) required in the empty space above the wine to maintain the minimum molar concentration determoned in part B. Formulas for part C: Sg = kPg, k = 3.4 x 10^ -2 mol/ (L atm)

Explanation / Answer

A. Given 3.92g of CO2 is present in 1 litre of solution.

ppm is parts per million.

In order to calculate the parts per million you will need to know how many mg of solute is dissolved in 1000g (1L) of water.

that is 3920mg of CO2 is present in 1 lit.

then how many milligrams is present in 1000 lit.?

= 3920mg x 1000lit/1lit

= 3920000mg

= 3.92 ppm

B. Molarity = number of moles of solute/volume of solution in litres

no.of moles of solute = given mass of solute/its molecular mass

                                   = 3.92g/44g/mol

                                   = 0.089mol

Molarity = 0.089mol/1lit.

= 0.089,M

C: Determine the partial pressure of CO2 (in atmospheres) required in the empty space above the wine to maintain the minimum molar concentration 0.089M can be calculated as shown below:

Sg = kPg

Pg = Sg/k

     = .0.089mol/L/3.4 x 10^ -2 mol/ (L atm)

     = 2.62atm

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