The anodic react ion is Cu(s) rightarrow Cu^2+ (aq) + 2e^- Ag^+(aq) + e^- righta

Question

The anodic react ion is Cu(s) rightarrow Cu^2+ (aq) + 2e^- Ag^+(aq) + e^- rightarrow Ag(s) Ag(s) rightarrow Ag^+ (aq) + e^- Cu^2(aq) + 2e^- rightarrow Cu(s) The oxidizing agent is Cu(s) Cu^2+(aq) Ag^+(aq) Ag(s) The voltaic cell schematic diagram is Ag(s) | Ag^+(aq) || Cu^2+ (aq) | Cu(s) Cu^2+ (aq) | Cu(s) || Ag^+(aq) | Ag(s) Ag^+(aq) | Ag(s) || Cu(s) | Cu^2+(aq) Cu(s) | Cu^2+ (aq) || Ag^+(aq) | Ag(s) The anion in this cell is NO^- _3(aq) travelling to the Cu(s) electrode. Cu^2+(aq) travelling towards the Cu(s) electrode. Ag^+(aq) travelling towards the Ag(s) electrode. NO^- _3(aq) travelling to the Cu^2+ in solution around the Cu(s) electrode.

Explanation / Answer

(1) Anode reaction occurs at left side compartment.

(a) Cu (s) ----------> Cu2+ (aq.) + 2 e

(2) Oxidising agent is the species that undergoes reduction.

(c) Ag+ (aq.)
(3) (d)

(4) (d)

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