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PART 1: Concentration of vitamin Cin fruit juice: DATA: FRUIT JUICE: Type of jui

ID: 526048 • Letter: P

Question

PART 1: Concentration of vitamin Cin fruit juice: DATA: FRUIT JUICE: Type of juice Luaneery volume of container: 295 Servings per container: l Volume per servi RDA for vitamin C: 90 mg RDA of vitamin C per serving: calculated concentration of vitamincbased on packaging: 30 mg/mL calculated molar concentration of vitamin cbased on packaging: l.13 mol/L (assume molar mass is equal to that of ascorbic acid, 176.12 g/mol) Titration Data: s. xio /mb Concentration of lodine Standard (on bottle) o-oosm. Trial 2 Trial 1 Trial 3 Initial Buret Reading: Final Buret Reading: volume of lodine solution: laL Moles of lodine Added. 4. 35 Jo2. .4, ID Moles of Vitamin Cin solution: 3 Measured concentration of vitamin Cin fruit juice (mol/L): 8 SAIO /u. concentration of vitamin cin fruit juice (mol/L) /L Error relative to label Concentrat on vitaman c O. 30S /L 73 x 10 mol 176.12 Inol 20 5mlml o,

Explanation / Answer

Trial 1

Molarity of Iodine solution=0.005 M

Volume of Iodine consumed=Final buret reading-initial buret reading=8.9 mL-0.2 mL=8.7 mL=8.7x10-3 L (as 1L=1000 mL)

Molarity of Vitamin C=To be determined

Volume of Vitamin C consumed=295 mL=0.295 L (as 1L=1000 mL)

In titration of Vitamin C with iodine, at the equivalence point

number of moles of Iodine=number of moles of Vitamin C

i.e Molarity of IodinexVolume of Iodine consumed=0.005 Mx8.7x10-3 L=4.35x10-5 mol=Molarity of Vitamin CxVolume of Vitamin C consumed

(Since Molarity=number of moles of solute/Volume of solution in L)

So 0.005 Mx8.7x10-3 L=Molarity of Vitamin Cx0.295 L

Molarity of Vitamin C=0.005 Mx8.7x10-3 L/0.295 L=1.47x10-4 M

Trial 2

Molarity of Iodine solution=0.005 M

Volume of Iodine consumed=Final buret reading-initial buret reading=9.7 mL-0.9 mL=8.8 mL=8.8x10-3 L (as 1L=1000 mL)

Molarity of Vitamin C=To be determined

Volume of Vitamin C consumed=295 mL=0.295 L (as 1L=1000 mL)

In titration of Vitamin C with iodine, at the equivalence point

number of moles of Iodine=number of moles of Vitamin C

i.e Molarity of IodinexVolume of Iodine consumed=0.005 Mx8.8x10-3 L=4.4x10-5 mol=Molarity of Vitamin CxVolume of Vitamin C consumed

(Since Molarity=number of moles of solute/Volume of solution in L)

So 0.005 Mx8.8x10-3 L=Molarity of Vitamin Cx0.295 L

Molarity of Vitamin C=0.005 Mx8.8x10-3 L/0.295 L=1.49x10-4 M

Average concentration of Vitamin C in fruit Juice in mol/L=(1.47x10-4 M+1.49x10-4 M)/2=1.48x10-4 M

%Error relative to label={(Experimental value-Theoretical value)/Theoretical value}x100 %=(1.48x10-4 M-1.73x10-3 M)/1.73x10-3M

=-91.44%