Use standard free energies of formation to calculate G at 25C for each of the fo

Question

Use standard free energies of formation to calculate G at 25C for each of the following reactions.

Part B

NH4I(s)HI(g)+NH3(g)

Express your answer using one decimal place.

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Part C

H2(g)+FeO(s)Fe(s)+H2O(g)

Express your answer using one decimal place.

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Part D

N2(g)+3H2(g)2NH3(g)

Express your answer using one decimal place.

Use standard free energies of formation to calculate G at 25C for each of the following reactions.

Part B

NH4I(s)HI(g)+NH3(g)

Express your answer using one decimal place.

Grxn= kJ

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Part C

H2(g)+FeO(s)Fe(s)+H2O(g)

Express your answer using one decimal place.

Grxn= kJ

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Part D

N2(g)+3H2(g)2NH3(g)

Express your answer using one decimal place.

Explanation / Answer

Answer :

Formula : G°rxn = G°f (products) - G°f (reactants)

Part B) Given physicochemical Transformation.

NH4I(s)HI(g)+NH3(g)

Thence,

G°rxn = G°f (products) - G°f (reactants)

G°rxn = [G°f HI(g) + G°f NH3 (g)] - G°f NH4I(s)

G°rxn = [(+1.3) + (-16.4)] - (-112.5)

G°rxn = +97.4 kJ

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Part C)

Given Physicochemical transformation,

H2(g)+FeO(s)Fe(s)+H2O(g)

G°rxn = [G°f H2O(g) + G°f Fe(s)] - [G°f H2(g) + G°f FeO(s)]

G°rxn = [(-228.6) + (0)] - [(0) + (-245.4)]

G°rxn = +16.8 kJ.

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Part D) Given Physicochemical Transformation,

N2(g)+3H2(g)2NH3(g)

G°rxn = G°f (products) - G°f (reactants)

G°rxn = [2 G°f NH3 (g)] - [3xG°f H2(g) + G°f N2(g)]

G°rxn = [2 x (-16.4)] - [3 x (0) + (0)]

G°rxn = - 32.8 kJ

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