Exercise 14.56 with eText link MasteringChemistry 10 of 16 Exercise 14.56 with e
ID: 525323 • Letter: E
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Exercise 14.56 with eText link MasteringChemistry 10 of 16 Exercise 14.56 with eText link Determine [H3O+] in each acid solution. If the acid is weak, indicate the value that [H3O+] is less than. Part A 0.125 M HClO2 0.125 [H3O+]=0.125 M [H3O+]<0.250 M [H3O+]=0.0625 M [H3O+]<0.125 M SubmitGive Up Part B 1.25 M H3PO4 1.25 [H3O+]<3.75 M [H3O+]<1.25 M [H3O+]=3.75 M [H3O+]=1.25 M SubmitGive Up Part C 2.77 M HCl 2.77 [H3O+]=5.54 M [H3O+]<2.77 M [H3O+]=2.77 M [H3O+]<5.54 M SubmitGive Up Part D 0.95 M H2SO3 0.95 [H3O+]<1.90 M [H3O+]<0.95 M [H3O+]=1.90 M [H3O+]=0.95 M SubmitGive Up Continue
Exercise 14.56 with eText link MasteringChemistry 10 of 16 Exercise 14.56 with eText link Determine [H3O+] in each acid solution. If the acid is weak, indicate the value that [H3O+] is less than. Part A 0.125 M HClO2 0.125 [H3O+]=0.125 M [H3O+]<0.250 M [H3O+]=0.0625 M [H3O+]<0.125 M SubmitGive Up Part B 1.25 M H3PO4 1.25 [H3O+]<3.75 M [H3O+]<1.25 M [H3O+]=3.75 M [H3O+]=1.25 M SubmitGive Up Part C 2.77 M HCl 2.77 [H3O+]=5.54 M [H3O+]<2.77 M [H3O+]=2.77 M [H3O+]<5.54 M SubmitGive Up Part D 0.95 M H2SO3 0.95 [H3O+]<1.90 M [H3O+]<0.95 M [H3O+]=1.90 M [H3O+]=0.95 M SubmitGive Up Continue
Exercise 14.56 with eText link MasteringChemistry 10 of 16 Exercise 14.56 with eText link Determine [H3O+] in each acid solution. If the acid is weak, indicate the value that [H3O+] is less than. Part A 0.125 M HClO2 0.125 [H3O+]=0.125 M [H3O+]<0.250 M [H3O+]=0.0625 M [H3O+]<0.125 M SubmitGive Up Part B 1.25 M H3PO4 1.25 [H3O+]<3.75 M [H3O+]<1.25 M [H3O+]=3.75 M [H3O+]=1.25 M SubmitGive Up Part C 2.77 M HCl 2.77 [H3O+]=5.54 M [H3O+]<2.77 M [H3O+]=2.77 M [H3O+]<5.54 M SubmitGive Up Part D 0.95 M H2SO3 0.95 [H3O+]<1.90 M [H3O+]<0.95 M [H3O+]=1.90 M [H3O+]=0.95 M SubmitGive Up Continue
Explanation / Answer
Part A. 0.125 M HClO2, is a moderately strong acid, and dissociation constant Ka = 1.1×10–2
HClO2 + H2O ---------.>H3O+ + ClO2-
at equlibirium concentrations of [H3O+] = X, [ClO2-] = X, [HClO2] = 0.125-X
Ka = [H3O+] [ClO2-]/ [HClO2]
1.1 x 10-2 = [X] [X] / [0.125 -X]
1.1 x 10-2 [0.125 -X] = X2
0.001375 - 0.011 X = X2
X2 + 0.011X - 0.001375 =0
using the quadratic equation at
X = 0.032 M
it is [H3O+]<0.0625 m
Part B. 1.25 M H3PO4 is moderate acid whose Ka's show it in quite weaker. In a solution that has only water and phosphoric acid there are four possible sources of hydrogen ion, the water and the three ionizations of the phosphoric acid. Each ionization has a different Ka.
Ka1 =7.1×10–3 , Ka2 = 6.3×10–8, Ka3 = 4.2×10–13
expect it to be [H3O+]<1.25 M
Part C. 2.77 M HCI, is a very strong acid
HCl -------- H+ + Cl-
[H+] = [HCl] = 2.77M
[H+]= [H3O+]=2.77 M
Part D. 0.95 M H2SO3 , is not much different than HClO2 in strength, its Ka's are
Ka1 = 1.3×10–2 (only the 1st H+ releases to any great concern)
Ka2 = 6.2×10–8 (so weak it doesn't even matter )
[H3O+]<0.95
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