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BE 96% Thu 5:01 PM QA E Chrome File Edit View History Bookmarks People Window Help Mastering Chemistry: Post Lecture Homework Chapter 13 Secure https session.masteringchemistry.co 78496347 m/m Chem 132-02 Help Close Post Lecture Homework Chapter 13 Exercise 13.89 Google Chrome Resources previous l 14 of 15 l next Exercise 13.89 Search Part A AN2 What mass of salt (NaCl) should you add to 1.78 Lof water in an ice cream maker to make a solution that freezes at -11.0°C? Assume complete dissociation of the NaCl and density of 1.00 g/mL for water. a question from our experts fo (NaCl ork questions Submit My Answers Give Up uestion incorrect; Try Again; 4 attempts remaining CONTINUE TO PO Continue Provide Feedback 13 questions remainin xtbook Solutions Solutions Principles...Explanation / Answer
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Depression in freezing poiont = 1000 * Kf w / W m ------ (1)
Where,
depression in freezing point = 0.00 - ( - 11.0 ) = + 11.0
Kf of water = 1.86 0C kg./mol
w = mass of solute = ?
W = mass of salvent = 1.78 L * 1 kg/L = 1.78 kg = 1780 g.
m = molar mass of solute = 35.5 + 23 = 58.5 g/mol
therefore from (1)
11.0 = 1000 * 1.86 * w / (1780 * 58.5)
w = mass of solute = 616. g. = 0.616 kg.
Mass of NaCl to be added = 0.616 kg.
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