Describe succinctly how you would separate a mixture of two alcohols, A and B, b

Question

Describe succinctly how you would separate a mixture of two alcohols, A and B, boiling at different temperatures into quasi-pure A and B. Given: Fe(s) + Br_2(l) FeBr_2(s); + H = - 249.8 KJ FeBr_3(s) FeBr_2(s) + 1/2 Br_2(l); + H = +18.4 KJ Calculate the heat of formation Fe(s) + 3/2 Br_2(l) FeBr_3(s) Which of the above reactions is endothermic C_2H_2(g) + 5/2 O_2(g) 2CO_2(g) + H_2O(l) +H = 1296 KJ Calculate the heat of formation of C_2H_2(g) Given that +Hf CO_2(g) = -393.5 KJ/mol +Hf H_2O(l) = - 285.8 KJ/mole

Explanation / Answer

(3)

The tow alcohols can be separated by distillation process, in which the alcohol with lower boiling point boils out first and gets separated from the other

(4)

The reaction 2 is endothermic because its dH value is +ve

Reaction 3 is the result of reversing reaction 2 and then adding it to reaction 1.

So heat of formation = -249.8 - (18.4) = -268.2 kJ

(5)

dHrxn = dHf(products) - dHf(reactants) = ( 2*dHf(CO2) + dHf(H2O) ) - ( dHf(C2H2) + 5/2*dHf(O2) )

Putting values:
1296 = ( 2*(-393.5) + (-285.8) ) - ( dHf(C2H2) + 5/2*0 )

So,

dHf(C2H2) = -2368.8 kJ/mole

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