Rank these resonance structures from the most important contributor to the reson
ID: 524747 • Letter: R
Question
Rank these resonance structures from the most important contributor to the resonance hybrid to the least important. (A) 1 > 2 > 3 (B) 3 > 1 > 2 (C) 2 > 3 > 1 (D) 2 > 1 > 3 Predict the hybridization and the bond angles around the central carbon in: (A) sp^2, 120 degree (B) sp^3, 109.5 degree (C) sp^2, 109.5 degree (D) sp^3, 120 degree In the lowest energy conformer of cis-1, 3-dimethylcyclohexane, how many axial positions are occupied by hydrogen atoms? (A) 2 (B) 3 (C) 5 (D) 6 Which hybridized orbitals overlap to make the bond indicated with an arrow? (A) C_a sp^2 - C_b sp^2 (B) C_a sp^3 - C_b sp^2 (C) C_a sp^2 - C_b sp^3 (D) C_a sp^3 - C_b sp^3 List the carbocations in order of decreasing stability. (A) 1 > 3 > 4 > 2 (B) 4 > 2 > 3 > 1 (C) 3 > 1 > 2 > 4 (D) 4 > 2 > 1 > 3Explanation / Answer
5. A. 1 > 2 > 3 [ The most stable structure is the structure which has low formal charge on the atom; In 1 all the atoms have 0 formal charge; among 2 and 3, 2 is more stable becuase the negative formal charge in O is stable than N. The electronegativity of O is more than N.]
6. A. sp2, 1200
7. D.6 [ in cis- 1,3 -dimethyl cyclohexane the methyl group occupies either axial position or equatorial position. if it occupies axial position then no of hydrogen atom occupies axial position are 4 whereas if it occupies euatorial position then no of hydrogen atom occupies axial position are 6.]
8. C. Casp2 - Cbsp3 [ The C=O is sp2 hybridised and the next C is sp3 hybridised (all bonds are single bond)
9. D. 4 > 2> 1>3. [ tertiary carbocation is more stable than secondary carbocation hence 4 is more stable; among 1, 2 and 3, 2 is more stable because methyl group stabiilised the cation by + I-effect whereas 1 and 3 is less stable becuae of - I - effect. 1 is more stable than 3, F is more electronegative than Cl so F destabilised the cation.
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