Sorry, this is a long question but I do not understand how to determine the volu

Question

Sorry, this is a long question but I do not understand how to determine the volume of each concentration of HCl that I need for the chromatographic separation experiment. Also, how to prepare each of the diluted solutions from a 6M HCl stock solution? Please Help

Thank you

metal. Similar hydrated equilibrium constant, and these ion such is in turn are different for each to (1) (2) (3) by is the converted symbol which represented as Fe constants series MC12 MC13 MC1+ MCI42 as no trivalent transition expressed follows: at of the for Cl C1 Cl C1 first a form may of MC13 Mci MC12 M2+ an be written ion its equations own involved If equilibria has the BACKGROUND step

Explanation / Answer

For HCl Formula weight is same Molar weight is same. Therefore Molarity could be calculated easily calculated. HCl is polar and therefore it would shorten the retention time on HPLC.

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