Reduction involves the increase in _________ and decrease in._______. a. oxygen,
ID: 523280 • Letter: R
Question
Reduction involves the increase in _________ and decrease in._______. a. oxygen, hydrogen b. carbon, oxygen c. hydrogen, oxygen d. oxygen, carbon Potassium Permanganate (KMnO_4) is commonly used to oxidize _______ alcohols to carboxylic acids. a. secondary b. tertiary c. primary d. none of the above Sodium Borohydride (NaBH_4) is most commonly used for reduction of ____ and _______ to alcohols. a. ketones, aldehydes b. carboxylic acids, ketones c. aldehydes, carboxylic acids d. ester, carboxylic acids Both reducing and oxidizing agents are typically ________ compounds. a. organic b. metallic c. ionic d. inorganic A correct IUPAC name of the compound below is: a. 1-Bromo-1-methyl-2, 5-cyclohexadiene b. 3-Bromo-3-methyl-1, 4-cyclohexadiene c. 6-Bromo-6-methyl-1, 4-cyclohexadiene b. 2-Bromo-2-methyl-1, 3-cyclohexadieneExplanation / Answer
Answer to Q 19 is c
In reduction the electrons are gained while they are lost in oxidation. In terms of oxygen and hydrogen, reduction means gain of hydrogen and loss of oxygen. While oxidation is gain of oxygen. E.g. ethanal is reduced to ethanol by gaining hydrogen.
CH3CHO + H2 -----> CH3CH2OH
Answer to Q 20 is c
Primary alcohols can be oxidised to carboxylic acids. KMnO4 is a strong oxidising agent and provides [O] for the oxidation of alcohols. Secondary alcohols can be oxidised to ketones and not acids and tertiary alcohols are resistant to oxidation.
CH3CH2OH + [O] -------> CH3COOH
Answer to Q 21 is a
Sodium borohydride is a good reducing agent but not very powerful. It can reduce aldehydes, ketones and acyl chlorides to corresponding alcohols but it cannot reduce esters, carboxylic acids or amides.
Answer to Q 22 is c
The oxidation or reduction potential of a compound is based on the ability to lose or gain electrons i.e. form ions. Hence most of them are ionic compounds.
Answer to Q 23 is b
If the parent chain contains double bond, an alkyl and a halo group, the double bond is given priority to have lowest number over the other two. The position of double bonds is indicated by assigning number to the first carbon of the double bond.
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.