Part 2: Change of State Equation practice : Substance Formula Hfus Hvapor Water
ID: 522774 • Letter: P
Question
Part 2: Change of State Equation practice:
Substance
Formula
Hfus
Hvapor
Water
H2O
6.01kJ/mol
40.7kJ/mol
H2O(l) H2O (s)
1)How much heat (in kJ) is released when 722g of water freezes at 0oC?
3) H2O(s) H2O (l)
How much heat in kJ is absorbed when 360. g of ice melts at 0oC?
Extra Credit: C(s) +2S (s) CS2(l) H = 90.0kJ use this for problems 5&6
5) How much heat (in kJ) is absorbed when 123g of carbon disulfide is formed?
6) How much heat (in kJ) is absorbed when 325g of sulfur is reacted?
Substance
Formula
Hfus
Hvapor
Water
H2O
6.01kJ/mol
40.7kJ/mol
Explanation / Answer
1)
mol of H2O = mass / molar mass
= 722 g / 18 g/mol
= 40.11 mol
Q released = Hfus * mol
= 6.01 KJ/mol * 40.11 mol
= 241 KJ
Answer: 241 KJ
3)
mol of ice melting = mass / molar mass
= 360 g / 18 g/mol
= 20 mol
Q absorbed = Hfus * mol
= 6.01 KJ/mol * 20 mol
= 120 KJ
Answer: 120 KJ
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