You MUST show your work to receive any credit. The quiz will be due at the begin

Question

You MUST show your work to receive any credit. The quiz will be due at the beginning of class on 5/4/17. A cell is made of the following half reduction reactions: Cu^2+ (aq) rightarrow Cu(s) E degree = 0.34 V O_2(g) + 2H_2O(l) rightarrow 4 OH^-(aq) E degree = 0.40 V Write the balanced reaction. Write the description of the cell using cell notation. Assume the oxygen electrode uses Pt(s). Determine E degree_cell for the spontaneous reaction. Find the Delta G degree for this cell. Find K for this cell under standard conditions.

Explanation / Answer

1. Pure Cu formed at cathode.

Cu+2 (aq)+ 2e-   -------------> Cu(s)

oxygen is released at anode.

OH-(aq) ------------> O2(g) + H2O(l)

4OH- -----------> O2 +2 H2O + 4 e-

by adding these two equations.

Cu+2 + 2e-   -------------> Cu multiply by '2'

2Cu+2 + 4e-   ------------->2 Cu

2Cu+2 + 4e- +4OH- -------------> 2Cu +O2 +2 H2O + 4 e-

2Cu+2 (aq) +4OH-(aq) -------------> 2Cu (s)+O2(g) +2 H2O(l)

Related Questions

Navigate

• Browse (All)
• Browse Y
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.