The hydrogenation of ethylene occurs by the following equilibrium: When solid NH

Question

The hydrogenation of ethylene occurs by the following equilibrium:

When solid NH_4 HS is placed in a closed flask at 28 degree C, the solid dissociates according to the equation NH_4 HS (s) SNH_3 (g) + H_2 S (g) The total pressure of the equilibrium mixture is 0.766 atm. Determine K_p at this temperature. a) 0.147 b) 0.766 c) 0.587 d) 0.383 e) 1.53 Consider the following exothermic reaction: N_2 (g) + 3 H_2 (g) 2 NH_3 (g) Which of the following changes would not increase the amount of NH_3 produced from given quantities of N_2 and H_2? a) increase in P b) increase in T c) decrease in V d) remove some NH_3 and reestablish equilibrium e) none of the above The hydrogenation of ethylene occurs by the following equilibrium: C_2 H_4 (g) + 2 H_2 (g) 2 CH_4 (g) K_p = 1.64 at 1000 K. A vessel is charged with a 1.00 atm sample of C_2 H_4 (g) and a 1.00 atm sample of H_2 (g). Estimate the pressure of methane gas after the system has reached equilibrium. a) 0.067 atm b) 0.13 atm c) 0.26 atm d) 0.52 atm e) 0.74 atm For the reaction SO_2 (g) + Ck_2 (g) SO_2 Cl_2 (g), K_c = 55.5 at a certain temperature. If 1.00 mole of SO_2 (g) and 1.00 mole of Cl_2 (g) are placed in a 10.0-L container and allowed to come to equilibrium, what is the equilibrium concentration of SO_2 Cl_2? a) 0.87 b) 0.066 c) 0.13 d) 0.034 e) 0.74 K = 0.25 for 2 NOBr (g) 2 NO (g) + Br_2 (g) At same T and P, what is the K for NO + 1/2 Br_2 NOBr? a) 2.0 b) 4.0 c) 0.50 d) 0.63 e) 1.0

Explanation / Answer

Ans 16 a . 0.147

For this reaction

Kp = [ NH3] [H2S]

Let each gas is formed x moles

So now ,

0.766 = x + x

X = 0.383

Substituting the value of X in the equation

Kp = 0.383 × 0.383

Kp = 0.147

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