All answers must start with the equation that was used to answer the question, a

Question

All answers must start with the equation that was used to answer the question, and all work must be shown.

3. The frequency of A1 among continental populations of bats is 0.94. On a nearby island, the frequency of A1 is 0.4. There are approximately 100 bats on the island, and each generation an average of one bat migrates from the continent to the island. How does the frequency of A1 on the island change from one generation to the next?        

3b. What is the rate of change of the allele frequency on the island as a function of migration?

Explanation / Answer

a) The equation used is px t+1 = px t [1-m] + py m.There are 2 populations: one is Island with frequencies of the A allele of 0.40 (px) and Continent with frequency of A allele as 0.94 (py) .

1 bat moves from continent to island every generation. The proportion of these Continent individuals that become parents in population Island in the next generation = 0.009 (m). After the migration, population Island can be considered to consist of migrant individuals (0.009) [px t(m)] and non-migrant individuals (0.98) [pxt[1-m]]. Thus the frequency of the A allele in population x in the next generation (px t+1) is just the frequency in the non-migrant portion (= px [1-m]) plus the frequency in the migrant portion (py m).

Hence, using the equation to calculate the frequency: px t+1 = px t [1-m] + py m.

= 0.98+ 0.94 (0.009)

=0.98846 ~ 0.99

b) The change in allele frequency is given by Dp = -m(px t - py t)

= -0.009(0.40-0.94)

= -0.00486

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