Univ. of Southern M x wwwsaplinglearning.con x C Chemistry question Che x G how

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Univ. of Southern M x wwwsaplinglearning.con x C Chemistry question Che x G how to screenshot on an x x C O www.sap nglea ning.com/ibiscms/m 3184153 /mod/ibis/view.php?id: 4/28/2017 05:00 PM A 83/100 4/28/2017 12:55 PM Gradebook O Assignment Information Attempts Score t Print Calculator Periodic Table Available From 4/11/2017 08:00 AM Question 23 of 23 4/28/2017 05:00 PM Due Date Map General Chemistry Athedton University Science Books Points Possible prosented by Sapling Loaming Grade Category: Graded Consider the following Gibbs energies at 25 C. Description: Substance AG J.mol Policies USM-2 Att. 109% Ag (aq) 85 131.2 You can check your answers 109.8 04.0 You can view solutions when you complete or give 96.9 up on any question. 90 (a) Calculate AG an for the dissolution of AgCl(s). b) Calculate the solubility-product constant of AgCl You can keep trying to answer each question until you get it right or give up. Number Number You lose 10% of the points available to each kJ mol answer in your question for each incorrect attemp 80 (c) Calculate AGron for the dissolution of AgBr(s), d) Calculate the solubility-product constant of AgBr. Number Number O eTextbook kJ mol 20 80 O Help With This Topic o Web Help & Videos 22 O Technical Support and Bug Reports A Previous ® Give Up & View solution 2 Check Answer 0Next Exit 3:06 PM Type here to search 4/28/2017

Explanation / Answer

a)

dG for AgCl(s)

Ag(+) + Cl- = AgCl(s)

dG = AgCl - (Ag+ + Cl-)

dG = (-109.8) - (77.1 + -131.2)

dG = -55.7 kJ/mol

b)

K from

dG = -RT*lnK

K = exp(-dG/(RT))

K = exp(55700/(8.314*298))= 5803271904.14

K = 5.8*10^9

c)

dG = AgBr - (Ag+ + Br-)

dG = -96.9 - (77.1 + -104) = -70 kJ/mol

d)

dG = -RT*lnK

K = exp(-dG/(RT))

K = exp(70000/(8.314*298))= 1.8634*10^12

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